Find the value of p and q. \(\large \left(\frac{1~×~x_2~+~1~×~x_1}{1~+~1}, \frac{1~×~y_2~+~1~×~y_1}{1~+~1}\right)\). Math Class 10 math (India) Coordinate geometry Section formula. So, the coordinates of the point P(x, y) which divides the line segment joining the points A(x1, y1) and B(x2, y2), internally, in the ratio m1 : m2 are { (m1x2 + m2x1)/(m1 + m2 ) , (m1y2 + m2y1)/(m1 + m2 ) } .This is known as the section formula. CE = BD = OB – OD = (x1 – x) units Let us understand it’s proof with an Example: C(x, y) is a point which divides the line OA in the ratio 2 : 1, where point O is origin. \(\large \frac{-2~+~p}{2}\) = \(\large \frac{-1+3}{2}\), \(\large\frac{3~+~q}{2}\) = \(\frac{9~-~1}{2}\). ⇒ OC = 2a units Let's apply Section formula to find the coordinates of the point or the ratio in which it divides the line or the coordinates of either of the end points. \(m\) = \(n\) = \(1\). Please keep a pen and paper ready for rough work but keep your books away. 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